How do I check if a value is a valid URL in Python without using regular expressions?
Antek N

To check if a value is a valid URL in Python without using regular expressions, you can utilize theurllib.parse module, which provides functions for URL parsing and manipulation. Here's a detailed explanation of how to accomplish this: Using theurllib.parse module: 1. Import theurllib.parse module: Begin by importing theurllib.parse module, which contains the necessary functions for URL parsing.

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   from urllib.parse import urlparse

2. Create a validation function: Define a function that takes a value and checks if it is a valid URL.

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   def is_valid_url(value):
  try:
 result = urlparse(value)
 return all([result.scheme, result.netloc])
  except (ValueError, TypeError):
 return False

3. Call the validation function: Use theis_valid_url() function to check if a value is a valid URL. The function uses theurlparse() function to parse the URL and then checks if both the scheme and network location (domain) are present, indicating a valid URL.

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   value = "https://www.example.com"

   if is_valid_url(value):
  print("The value is a valid URL.")
   else:
  print("The value is not a valid URL.")

In this example, the value"https://www.example.com" is checked using theis_valid_url() function. Since it contains both a valid scheme (https) and a network location (www.example.com), the function returnsTrue, indicating that the value is a valid URL. Summary: To check if a value is a valid URL in Python without using regular expressions, you can utilize theurllib.parse module. By parsing the URL usingurlparse() and verifying the presence of both the scheme and network location, you can determine if the value adheres to the URL format. This approach provides a reliable way to validate URLs within your Python code without resorting to regular expressions.

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