How do I check if a string is a valid UUID4 in Python?Gable E
To check if a string is a valid UUID4 (Universally Unique Identifier version 4) in Python, you can use various approaches. Here's a long-form explanation of different methods to accomplish this:
1. Using theuuid
module:
- Python's built-inuuid
module provides functions and classes for working with UUIDs.
- Import theuuid
module and use theUUID()
function to attempt to create a UUID object from the string.
- If the creation succeeds without raising aValueError
exception and the UUID version is 4, it means the string is a valid UUID4.
- Example:
1 2 3 4 5 6 7 8 9
import uuid def is_valid_uuid4(string): try: uuid_obj = uuid.UUID(string) return uuid_obj.version == 4 except ValueError: return False
2. Using Regular Expressions:
- Regular expressions can be used to match and validate the format of a UUID4.
- You can import there
module and define a regular expression pattern that matches the standard format of a UUID4.
- The patternr'^[0-9a-fA-F]{8}-[0-9a-fA-F]{4}-4[0-9a-fA-F]{3}-[89aAbB][0-9a-fA-F]{3}-[0-9a-fA-F]{12}$'
matches a string consisting of five groups of hexadecimal characters separated by hyphens, with the fourth group starting with4
and the fifth group's first character being8
,9
,a
,A
,b
, orB
.
- Use there.match()
function to check if the entire string matches the pattern.
- If it matches, returnTrue
; otherwise, returnFalse
.
- Example:
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import re def is_valid_uuid4(string): pattern = r'^[0-9a-fA-F]{8}-[0-9a-fA-F]{4}-4[0-9a-fA-F]{3}-[89aAbB][0-9a-fA-F]{3}-[0-9a-fA-F]{12}$' return bool(re.match(pattern, string))
Choose the method that best suits your requirements. Each approach checks if a string is a valid UUID4, but they differ in terms of validation criteria, supported formats, and potential overhead.
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